[已答复] 三维图形

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夕木小径 发表于 2021-5-2 16:14:30
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syms A1 B1 C1 D1 E1 F1  A2 B2 C2 D2 E2 F2 N Ss Sc m11 m12 m13 m14 m21 m22 m23 m24 m31 m32 m33 m34 m41 m42 m43 m44  Psi delt sigma1 sigma2 theta1 theta2 Y1 Y2 X1 X2 U1 V1 U2 V2

% {
% sigma1=45;
% sigma2=60;
% theta1=30;
% theta2=45;
% }

N=cosd(2*Psi);
Sc=sind(2*Psi)*cosd(delt);
Ss=sind(2*Psi)*sind(delt);

A1=1-(1-cosd(sigma1))*sind(2*theta1)*sind(2*theta1);
A2=1-(1-cosd(sigma2))*sind(2*theta2)*sind(2*theta2);
B1=(1-cosd(sigma1))*sind(2*theta1)*cosd(2*theta1);
B2=(1-cosd(sigma2))*sind(2*theta2)*cosd(2*theta2);
C1=sind(sigma1)*sind(2*theta1);
C2=sind(sigma2)*sind(2*theta2);
D1=1-(1-cosd(sigma1))*cosd(2*theta1)*cosd(2*theta1);
D2=1-(1-cosd(sigma2))*cosd(2*theta2)*cosd(2*theta2);
E1=sind(sigma1)*cosd(2*theta1);
E2=sind(sigma2)*cosd(2*theta2);
F1=cosd(sigma1);
F2=cosd(sigma2);

W2=[1 0 0 0;0 A2 B2 -C2;0 B2 D2 F2;0 C2 -E2 F2];
S=[1 -N 0 0;-N 1 0 0;0 0 Sc Ss;0 0 -Ss Sc];
W1=[1 0 0 0;0 A1 B1 -C1;0 B1 D1 F1;0 C1 -E1 F1];
M=W2*S*W1;

%{
m11=M(1,1);
m12=M(1,2);
m13=M(1,3);
m14=M(1,4);
m21=M(2,1);
m22=M(2,2);
m23=M(2,3);
m24=M(2,4);
m31=M(3,1);
m32=M(3,2);
m33=M(3,3);
m34=M(3,4);
m41=M(4,1);
m42=M(4,2);
m43=M(4,3);
m44=M(4,4);
%}

sigma1=30;
sigma2=30;
theta1=30;
theta2=30;

%{
Psi=(-2*pi:pi:2*pi);
delt=(-2*pi:pi:2*pi);
%}

[Psi,delt] = meshgrid(-2*pi:2*pi);
% m24=cos((pi*sigma1)/180)*(sin((pi*Psi)/90)*sin((pi*delt)/180)*sin((pi*sigma2)/180)*sin((pi*theta2)/90) - sin((pi*Psi)/90)*cos((pi*delt)/180)*cos((pi*theta2)/90)*sin((pi*theta2)/90)*(cos((pi*sigma2)/180) - 1)) - cos((pi*sigma1)/180)*(sin((pi*Psi)/90)*cos((pi*delt)/180)*sin((pi*sigma2)/180)*sin((pi*theta2)/90) + sin((pi*Psi)/90)*sin((pi*delt)/180)*cos((pi*theta2)/90)*sin((pi*theta2)/90)*(cos((pi*sigma2)/180) - 1)) - sin((pi*sigma1)/180)*sin((pi*theta1)/90)*(sin((pi*theta2)/90)^2*(cos((pi*sigma2)/180) - 1) + 1)
% m42=sin((pi*sigma2)/180)*sin((pi*theta2)/90)*(sin((pi*theta1)/2490)^2*(cos((pi*sigma1)/180) - 1) + 1) + sin((pi*sigma1)/180)*sin((pi*theta1)/90)*(sin((pi*Psi)/90)*cos((pi*delt)/180)*cos((pi*sigma2)/180) - sin((pi*Psi)/90)*sin((pi*delt)/180)*cos((pi*theta2)/90)*sin((pi*sigma2)/180)) + cos((pi*theta1)/90)*sin((pi*theta1)/90)*(sin((pi*Psi)/90)*cos((pi*sigma2)/180)*sin((pi*delt)/180) + sin((pi*Psi)/90)*cos((pi*delt)/180)*cos((pi*theta2)/90)*sin((pi*sigma2)/180))*(cos((pi*sigma1)/180) - 1);

mesh(Psi,delt,f)
% hold on;
% mesh(Psi,delt,f)
% hold off

set(gca,'xlim',[-2*pi,2*pi]);%设置x轴坐标范围
set(gca,'xtick',-2*pi:pi/2:2*pi)%设置x轴坐标间隔
set(gca,'XTickLabel',{'-2\pi','-3\pi/2','-\pi','-\pi/2','0','\pi/2','\pi','3\pi/2','2\pi'});%\pi=π
set(gca,'ylim',[-2*pi,2*pi]);%设置y轴坐标范围
set(gca,'ytick',-2*pi:pi/2:2*pi);%设置y轴坐标间隔
set(gca,'YTickLabel',{'-2\pi','-3\pi/2','-\pi','-\pi/2','0','\pi/2','\pi','3\pi/2','2\pi'});%\pi=π
xlabel('Ψ'),ylabel('Δ'),zlabel('');

求助:运行上述代码时,提示如下错误。目的是想画出矩阵M(2,4)的三维图形。矩阵M为穆勒矩阵
请教如何才能画出矩阵M(2,4)的三维图形。




4 条回复


20141303 发表于 2021-5-2 19:31:54
仅供参考,我这边报错是未定义变量f,在
  1. mesh(Psi,delt,f)
复制代码
之前应用类似
  1. f=3*Psi+2*delt;
复制代码
定义f变量的代码

夕木小径 发表于 2021-5-2 19:33:34
20141303 发表于 2021-5-2 19:31
仅供参考,我这边报错是未定义变量f,在之前应用类似定义f变量的代码

好的,我试试。多谢答疑

夕木小径 发表于 2021-5-2 19:48:04
夕木小径 发表于 2021-5-2 19:33
好的,我试试。多谢答疑

clc
close all
clear

syms A1 B1 C1 D1 E1 F1  A2 B2 C2 D2 E2 F2 N Ss Sc m11 m12 m13 m14 m21 m22 m23 m24 m31 m32 m33 m34 m41 m42 m43 m44  Psi delt sigma1 sigma2 theta1 theta2 Y1 Y2 X1 X2 U1 V1 U2 V2

N=cosd(2*Psi);
Sc=sind(2*Psi)*cosd(delt);
Ss=sind(2*Psi)*sind(delt);

A1=1-(1-cosd(sigma1))*sind(2*theta1)*sind(2*theta1);
A2=1-(1-cosd(sigma2))*sind(2*theta2)*sind(2*theta2);
B1=(1-cosd(sigma1))*sind(2*theta1)*cosd(2*theta1);
B2=(1-cosd(sigma2))*sind(2*theta2)*cosd(2*theta2);
C1=sind(sigma1)*sind(2*theta1);
C2=sind(sigma2)*sind(2*theta2);
D1=1-(1-cosd(sigma1))*cosd(2*theta1)*cosd(2*theta1);
D2=1-(1-cosd(sigma2))*cosd(2*theta2)*cosd(2*theta2);
E1=sind(sigma1)*cosd(2*theta1);
E2=sind(sigma2)*cosd(2*theta2);
F1=cosd(sigma1);
F2=cosd(sigma2);

W2=[1 0 0 0;0 A2 B2 -C2;0 B2 D2 F2;0 C2 -E2 F2];
S=[1 -N 0 0;-N 1 0 0;0 0 Sc Ss;0 0 -Ss Sc];
W1=[1 0 0 0;0 A1 B1 -C1;0 B1 D1 F1;0 C1 -E1 F1];
M=W2*S*W1;
m24=M(2,4);
sigma1=30;
sigma2=30;
theta1=30;
theta2=30;

[Psi,delt] = meshgrid(-2*pi:2*pi);

mesh(Psi,delt,m24)


set(gca,'xlim',[-2*pi,2*pi]);%设置x轴坐标范围
set(gca,'xtick',-2*pi:pi/2:2*pi)%设置x轴坐标间隔
set(gca,'XTickLabel',{'-2\pi','-3\pi/2','-\pi','-\pi/2','0','\pi/2','\pi','3\pi/2','2\pi'});%\pi=π
set(gca,'ylim',[-2*pi,2*pi]);%设置y轴坐标范围
set(gca,'ytick',-2*pi:pi/2:2*pi);%设置y轴坐标间隔
set(gca,'YTickLabel',{'-2\pi','-3\pi/2','-\pi','-\pi/2','0','\pi/2','\pi','3\pi/2','2\pi'});%\pi=π
xlabel('Ψ'),ylabel('Δ'),zlabel('');

我将f改为M(2,4),为什么会出错呢?M(2,4)它是M矩阵中的一个元素,同时也是一个函数表达式,用mesh(Psi,delt,m24)为什么不能画出三维函数图呢?还请前辈不吝赐教

20141303 发表于 2021-5-2 20:19:51
因为m24应该是与Psi和delt同等维度的矩阵,且为数值型
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